十进制转化二进制

NB的函数

ClimbCM posted @ Mar 13, 2009 07:37:24 AM in c常用函数整理 with tags c , 941 阅读

NB的函数

void fast_memcpy (uint8_t *to, uint8_t *from, size_t count){
 register size_t n = (count + 7) / 8; /* count > 0 assumed */
 uint8_t c = count % 8;
 switch(c){
  case 0: do { *to++ = *from++;
  case 7: *to++ = *from++;
  case 6: *to++ = *from++;
  case 5: *to++ = *from++;
  case 4: *to++ = *from++;
  case 3: *to++ = *from++;
  case 2: *to++ = *from++;
  case 1: *to++ = *from++;
   } while (--n > 0);
 } }

登录 *


loading captcha image...
(输入验证码)
or Ctrl+Enter